Subject: Simple newbie Q: literal as row title
From: "Dick Penny" <d_penny@xxxxxxx>
Date: Tue, 10 Mar 2009 08:56:41 -0700
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As a newbie I have some XSLT working thanks to this group. I have moved to a
"named template" so that I can call template with different arguments - is
OK.
But I cannot figure out how to get a "fixed literal" as title of final
summary
row.
*************************fragment
<!-- for each unique audit name -->
<xsl:for-each select="Row[@AuditName and
generate-id(.)=generate-id(key('audits', @AuditName))]">
<xsl:call-template name="one-row">
<xsl:with-param name="AuditN" select="@AuditName"/>
<xsl:with-param name="findings" select="key('audits', @AuditName)"/>
</xsl:call-template>
</xsl:for-each>
<!-- for all audits -->
<xsl:call-template name="one-row">
<xsl:with-param name="AuditN" select="TOTAL"/>
<xsl:with-param name="findings" select="/dsQueryResponse/Rows/Row"/>
</xsl:call-template>
*************************
Dick Penny
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