|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] passing parameters to XSL,what if no value in some cas
First time,code will go to 'else' part,it again returns to this form
and 'if' part executes.
<CODE>
my $parser = XML::LibXML->new();
my $xslt = XML::LibXSLT->new();
my $source = $parser->parse_file($xmlfile);
my $style_doc = $parser->parse_file($xslfile);
my $stylesheet = $xslt->parse_stylesheet($style_doc);
if($in{'flag'} eq "2") {
my $results = $stylesheet->transform($source,
XML::LibXSLT::xpath_to_string(args => "$in{'args'}",val => "1",new =>
"$in{'new'}"));
print $stylesheet->output_string($results);
}else{
my $results = $stylesheet->transform($source,
XML::LibXSLT::xpath_to_string(args => "",val => "3",new =>
"$in{'new'}"));
print $stylesheet->output_string($results);
}
</CODE>
1.In my 'else' above,I don't want to pass 'args'(can I do it?),
2.How can I check in my xsl file whether it is passed or not probably
using some 'if' statement or something like this?
<CODE>
<xsl:choose>
<xsl:when test="args_is_given">
<some code>
</xsl:when>
</xsl:choose>
</CODE>
-----------------------------
Regards,
Himanshu Padmanabhi
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|






