Subject: Re: xsl:for-each-group and identity transform
From: David Carlisle <davidc@xxxxxxxxx>
Date: Fri, 23 Jan 2009 14:58:35 GMT
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> I guess is never going to work, we need "current-group()". I simply
> can't see how we can get the modified identity template into play.
not in the templates that you use to process the group (at least not
normally). I had to make some guesses as I had no input or expected
output but as I say the usual model is that you just have
<xsl:apply-templates select="current-group()"/>
as the content of the for-each-group, perhaps with a mode, if that's
needed, and then template matching proceeds as normal and can be the
identity template or any other.
<xsl:copy-of select="./node()"/>
or just node() as ./ doesn't do anything.
David
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