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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Tricky XSLT 2.0 grouping problem
 I have a tricky grouping problem that I'm running into a wall with. I
thought it might be a fun challenge to throw out there. I'm attempting
to group a flat list of <section> elements into a hierarchy based on
matching its number against different regular expressions. The list is
assumed to be in the correct order. I have it working (the code is
below) with one exception: roman numerals.
For example, the XML:
<body>
<section><pnum>(a)</pnum><p>First-level section</p></section>
<section><pnum>(1)</pnum><p>Second-level section</p></section>
<section><pnum>(A)</pnum><p>Third-level section</p></section>
<section><pnum>(i)</pnum><p>Fourth-level section</p></section>
<section><pnum>(ii)</pnum><p>Fourth-level section</p></section>
<section><pnum>(B)</pnum><p>Third-level section</p></section>
<section><pnum>(2)</pnum><p>Second-level section</p></section>
<section><pnum>(A)</pnum><p>Third-level section</p></section>
</body>
Should give the result:
<body>
<section>
<pnum>(a)</pnum><p>First-level section</p>
<section>
<pnum>(1)</pnum><p>Second-level section</p>
<section>
<pnum>(A)</pnum><p>Third-level section</p>
<section><pnum>(i)</pnum><p>Fourth-level section</p></section>
<section><pnum>(ii)</pnum><p>Fourth-level section</p></section>
</section>
<section>
<pnum>(B)</pnum><p>Third-level section</p>
</section>
</section>
<section>
<pnum>(2)</pnum><p>Second-level section</p>
<section><pnum>(A)</pnum><p>Third-level section</p></section>
</section>
</section>
</body>
The problem is that the number "(i)," which is supposed to be a
fourth-level section, in ambiguous with an "(i)" that would be a
first-level section. My transform ends up treating it like a
first-level section, and so gives the following, incorrect output:
<body>
<section>
<pnum>(a)</pnum><p>First-level section</p>
<section>
<pnum>(1)</pnum><p>Second-level section</p>
<section>
<pnum>(A)</pnum><p>Third-level section</p>
</section>
</section>
</section>
<section>
<pnum>(i)</pnum><p>Fourth-level section</p>
<section>
<pnum>(ii)</pnum><p>Fourth-level section</p>
<section>
<pnum>(B)</pnum><p>Third-level section</p>
</section>
</section>
<section>
<pnum>(2)</pnum><p>Second-level section</p>
<section>
<pnum>(A)</pnum><p>Third-level section</p>
</section>
</section>
</section>
</body>
I've included my current transform below. The grouping_keys variable is
a sequence of regex strings that match each subsequent level of section
nesting. Does anybody have an alternate way of tackling this?
Thanks,
-James
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0">
<xsl:variable name="grouping_keys" as="xs:string+"
select="('\([a-z]\)', '\([1-9]\)', '\([A-Z]\)',
'\([ivx]{1,4}\)')" />
<!-- Start the grouping here -->
<xsl:template match="codebody">
<codebody>
<xsl:copy-of select="@*"/>
<xsl:for-each-group select="*"
group-starting-with="section[matches(pnum,
string($grouping_keys[1]))]">
<xsl:apply-templates select="." mode="group">
<xsl:with-param name="level" select="1"
as="xs:integer"/>
</xsl:apply-templates>
</xsl:for-each-group>
</codebody>
</xsl:template>
<!-- This template copies the current section and groups any
"nested" sections -->
<xsl:template match="section" mode="group">
<xsl:param name="level" as="xs:integer"/>
<section>
<xsl:copy-of select="@*, *"/>
<xsl:if test="$level < count($grouping_keys)">
<xsl:for-each-group select="current-group() except ."
group-starting-with="section[matches(pnum,
string($grouping_keys[$level + 1]))]">
<xsl:apply-templates select="." mode="group">
<xsl:with-param name="level" select="$level + 1"
as="xs:integer"/>
</xsl:apply-templates>
</xsl:for-each-group>
</xsl:if>
</section>
</xsl:template>
<xsl:template match="element()" mode="#all">
<xsl:copy>
<xsl:apply-templates select="@*,node()" mode="#current"/>
</xsl:copy>
</xsl:template>
<xsl:template
match="attribute()|text()|comment()|processing-instruction()"
mode="#all">
<xsl:copy/>
</xsl:template>
</xsl:stylesheet>
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