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Display link text as a hyperlink

Subject: Display link text as a hyperlink
From: Brent Solly <ultra@xxxxxxxxx>
Date: Thu, 7 Aug 2008 08:35:19 -0700 (PDT)
 Display link text as a hyperlink
Date: Wed, 6 Aug 2008 16:04:28 +0100
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx>
Subject: Re:  Display link text as a hyperlink
Message-ID: <74a894af0808060804w7b8319a6h8c4f3934c6f60353@xxxxxxxxxxxxxx>

whoooaaaaah there.... you've set off down the wrong road (like so many
others) and it will only end in tears and resentment.  It's completely
the wrong apporach.

To do a search and replace on a string use either replace() or

<xsl:analyze-string select="." regex="$the-regex">
    <a href="http://{.}">http://<xsl:value-of select="."/></a>
    <xsl:value-of select="."/>

Andrew Welch
Kernow: http://kernowforsaxon.sf.net/

I'm not sure if your code works in XSLT 1.0.  It doesn't appear to work in XSLT 1.0.  Currently looking into upgrading to XSLT 2.0.  

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