Re: position and loop problem
Tahnks > What do you wanna do exactly? what i am going to do is, to get the number of the "section" elements from the XML file, than make a loop which turns for so many time as the number of the "section" element existed in the XML file! I hope i was clear now . --- Florent Georges <lists@xxxxxxxxxxxx> schrieb: > henry human wrote: > > Hi > > > I save the number of a specific node as follow and > get > > the right number for the node which is 2: > > <xsl:variable name="var" > > > select="count(document/elements/element[@type='section'])"/> > > However when I try it in a for-each loop as follow > I > > get 6 times looping! > > Hier is the for-each loop: > > > <xsl:for-each select="//*[position() <= $var]"> > > position() doesn't behave as you seem to think it > does. What you get > means there are in the input tree 6 elements that > are the first or > second child of their parent element. > > What do you wanna do exactly? > > Regards, > > --drkm > > > > > > > > > > > > > > > > > > > > > > > > > _____________________________________________________________________________ > > Envoyez avec Yahoo! Mail. Une boite mail plus > intelligente http://mail.yahoo.fr > > __________________________________________________ Do You Yahoo!? Sie sind Spam leid? Yahoo! Mail verf|gt |ber einen herausragenden Schutz gegen Massenmails. http://mail.yahoo.com
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