Re: generating xml from xslt

Hi

Thanks for your help. Is there a quicker way of doing this instead of entering the value for the parameters everytime the transformation is run? I have xalan xslt processor. If I want to generate 50 files it will take a long time to run this transformaiton. 


--- On Tue, 8/26/08, Martin Honnen <Martin.Honnen@xxxxxx> wrote:

> From: Martin Honnen <Martin.Honnen@xxxxxx>
> Subject: Re:  generating xml from xslt
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Date: Tuesday, August 26, 2008, 3:59 PM
> Sarkup Sarkup wrote:
> 
> > <xsl:stylesheet version="1.0" 
> >
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> > <xsl:output method="xml"/>
> 
> 
> Define three global parameters
>    <xsl:param name="a1"/>
>    <xsl:param name="a2"/>
>    <xsl:param name="a3"/>
> so that you can provide values for the transformation then
> keep this 
> template
> 
> >  <xsl:template match="@*|node()">
> >   <xsl:copy>
> >    <xsl:apply-templates
> select="@*|node()"/>
> >   </xsl:copy>
> >  </xsl:template>
> 
> remove the following template
> 
> > <xsl:template
> match="/root/status/locn/loc1/address">
> > <xsl:element
> name="add1"></xsl:element>
> > <xsl:element
> name="add2"></xsl:element>
> > <xsl:element
> name="add3"></xsl:element>
> > </xsl:template>
> 
> and add three templates
>    <xsl:template match="add1">
>      <xsl:copy>
>        <xsl:value-of select="$a1"/>
>      </xsl:copy>
>    </xsl:template>
>    <xsl:template match="add2">
>      <xsl:copy>
>        <xsl:value-of select="$a2"/>
>      </xsl:copy>
>    </xsl:template>
>    <xsl:template match="add3">
>      <xsl:copy>
>        <xsl:value-of select="$a3"/>
>      </xsl:copy>
>    </xsl:template>
> -- 
> 
> 	Martin Honnen
> 	http://JavaScript.FAQTs.com/