Re: [xsl] XPath and noname namespace

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Subject: Re: XPath and noname namespace
From: George Cristian Bina <george@xxxxxxxxxxxxx>
Date: Mon, 14 Jul 2008 18:08:14 +0300

Because the local name is the same as the name in your example for the a element. If you will have <s:svg xmlns:s="http://www.w3.org/2000/svg"> <s:a>aadsf</s:a> </s:svg> than you will get different results.

Best Regards,
George
--
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com

Adam Komisarek wrote:

Hello!

I have found workaround but I wonder why it must be done in that way..
Is it some kind of bug in XPath?

I have simple document:<svg xmlns="http://www.w3.org/2000/svg">
<a>aadsf</a> </svg>

And now "//a" doesn't find a node.. I must use //*[local-name() =
'a'], but funny thing is that //*[name() = 'a'] works as well.. Why is
that?

Thanks,
Adam

Current Thread
XPath and noname namespace Adam Komisarek - 14 Jul 2008 14:52:36 -0000 Message not available G. Ken Holman - 14 Jul 2008 15:04:02 -0000 George Cristian Bina - 14 Jul 2008 15:08:30 -0000 <= David Carlisle - 14 Jul 2008 15:10:35 -0000

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