Re: Need to output an opening or closing tag by itself

This looks like what I need.  Thanks for all of the responses.

David

On Wednesday 25 June 2008 12:28:48 am Mukul Gandhi wrote:
> As you have discovered, your stylesheet is not a well-formed XML so it
> cannot work through the XML parser.
>
> This looks to me a positional grouping problem, which can be solved
> efficiently in XSLT 1.0 with the "sibling recursion" technique.
>
> Below is the stylesheet for the same.
>
> <?xml version="1.0"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
>    <xsl:output method="xml" indent="yes" />
>
>    <xsl:template match="/root">
>      <root>
>        <xsl:for-each select="e[@t = 'a']">
>          <e>
>            <xsl:apply-templates select="following-sibling::*[1]" />
>          </e>
>        </xsl:for-each>
>      </root>
>    </xsl:template>
>
>    <xsl:template match="*">
>      <xsl:if test="not(self::e[@t = 'b'])">
>        <xsl:copy-of select="." />
>        <xsl:apply-templates select="following-sibling::*[1]" />
>      </xsl:if>
>    </xsl:template>
>
> </xsl:stylesheet>
>
> On 6/25/08, David Frey <dpfrey@xxxxxxx> wrote:
> > I have a simple XSLT problem for the gurus.
> >
> >
> > This is my input document:
> > <root>
> >  <e t="a"/>
> >  <f/>
> >  <f/>
> >  <e t="b"/>
> > </root>
> >
> >
> > This is the output document I want to produce:
> > <root>
> >  <e>
> >    <f/>
> >    <f/>
> >  </e>
> > </root>