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Am 05.06.2008 um 23:28 schrieb Julie:
Thank you for your reply, Michael. I don't know if that is possible. I'll give you my complete test case, which should work even with XMLSpy ;-) - Michael M|ller-Hillebrand XML === <?xml version="1.0" encoding="UTF-8"?>
<PublicationContent>
<File>
<FileGuid>fileguid1</FileGuid>
<FileShortDescription>Help 1</FileShortDescription>
<ContentUnit>
<CuMetadata>
<BinaryType>no</BinaryType>
<CuHistoryGuid>cuhistguid1</CuHistoryGuid>
</CuMetadata>
<CuContent>
<Task>
<RelatedLinks>
<CuRef CuHistoryGuid="cuhistguid2">Related link
text</CuRef>
</RelatedLinks>
</Task>
</CuContent>
</ContentUnit>
</File>
<File>
<FileGuid>fileguid2</FileGuid>
<FileShortDescription>Help 2</FileShortDescription>
<ContentUnit>
<CuMetadata>
<BinaryType>no</BinaryType>
<CuHistoryGuid>cuhistguid2</CuHistoryGuid>
</CuMetadata>
</ContentUnit>
</File>
</PublicationContent>XSLT ==== <?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"><xsl:key name="targetFile" match="File" use=".//CuHistoryGuid/text ()"/> <xsl:template match="RelatedLinks/CuRef">
<a class="old" href="{@CuHistoryGuid}.html">
<xsl:apply-templates/>
</a>
<a class="new" href="{key('targetFile', @CuHistoryGuid)/
FileGuid/text()}.html">
<xsl:apply-templates/>
</a>
</xsl:template>
</xsl:stylesheet> Result ====== <?xml version="1.0" encoding="UTF-8"?> <a class="old" href="cuhistguid2.html"/> <a class="new" href="fileguid2.html"/> -- _______________________________________________________________ Michael M|ller-Hillebrand: Dokumentations-Technologie Adobe Certified Expert, FrameMaker Lvsungen und Training, FrameScript, XML/XSL, Unicode <http://cap-studio.de/> -- Tel. +49 (9131) 28747
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