RE: fallback to a default template in xsl processing
Hi, Thank you! I tried that and maybe I didn't set it up correctly....buts the nodes with 'named' templates (e.g., 'A' or 'B') were processed twice, once by the template with match='A' and the other by match='*'. Thanks for your help! Regards, April April L Daly Daly Web, Inc. ________________________________________ From: Jim Earley [xml.jim@xxxxxxxxx] Sent: Thursday, April 24, 2008 3:38 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: fallback to a default template in xsl processing One approach for this is to use the following: <xsl:template match="*"> ... </xsl:template> Jim Earley XML Architect Flatirons Solutions Corp. -----Original Message----- From: Daly, April [mailto:april@xxxxxxxxxxx] Sent: Thursday, April 24, 2008 1:29 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: fallback to a default template in xsl processing Hi! I have what I hope is a simple question for the xsl/xpath gurus! I would like to be able to apply a default template within xsl 1.0 if no match is found. Currently I'm using an ugly 'brute-force' approach using <xsl:choose>: <xsl:choose> <xsl:when test="name()='A' or name()='B'"> <xsl:apply-templates mode='namedTemplates' select='.'/> </xsl:when> <xsl:otherwise> <xsl:apply-templates mode='defaultTemplates' select='.'/> </xsl:otherwise> </xsl:choose> this is a simplfied example, but I hope it shows what I'm trying to do. Is there a better way to apply a named template if 'found' otherwise apply a default template? Thanks (in advance) for your help! April April L Daly Daly Web, Inc.
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