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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: for-each-group group-by existing and non-existing
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output indent="yes"/> <xsl:template match="/container"> <test> <xsl:for-each-group select="*[.//validation/@idref]" group-by=".//validation/concat(@idref,' == ',(@value,'true')[1])"> <group condition="{current-grouping-key()}"> <xsl:copy-of select="current-group()"/> </group> </xsl:for-each-group> </test> </xsl:template> </xsl:stylesheet> David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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