RE: Slow XSLT

> It is like if I was using [1], [2] to get the current Row 
> (Row[1], Row[2]) but the '.' does not work with the node set $set
> 
> Is that clearer?

No, I'm sorry, it isn't. Either you want to process the current row, or you
want to process the rows in $set - you keep talking about the "current" Row,
and then saying you don't want the current Row, you want a row in $set. You
can do either, but you seem to be confused about which you want.

Michael Kay
http://www.saxonica.com/