Re: Count Ancestors Up To But Not Including a Given Ty

> So a simple "../.." won't be reliable.  

perhaps this


<x>
<ol>
  <li>
   <ol>
    <li>
<y/>
    </li>
   </ol>
  </li>
</ol>

<ol>
  <li><p>
   <ol>
    <li>
<y/>
    </li>
   </ol></p>
  </li>
</ol>

<ol>
  <li>
   <ul>
    <li>
     <ol>
      <li>
<y/>
      </li>
     </ol>
    </li>
   </ul>
  </li>
</ol>

<ol>
  <li>
   <ul>
    <li><p>
     <ol>
      <li>
<y/>
      </li>
     </ol></p>
    </li>
   </ul>
  </li>
</ol>


</x>
<xsl:stylesheet version="2.0"
		xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
		xmlns:xs="http://www.w3.org/2001/XMLSchema"
		xmlns:f="data:,f"
		>

  <xsl:variable name="lists" select="QName('','ol'),QName('','ul')"/>

  <xsl:strip-space elements="*"/>
  <xsl:function name="f:same" as="element()*">
    <xsl:param name="n" as="element()"/>
    
    <xsl:sequence select="$n,$n/ancestor::*[node-name(.)=$lists][1][node-name(.)=node-name($n)]/f:same(.)"/>
  </xsl:function>

<xsl:template match="y">
:<xsl:value-of select="count(f:same(../..))"/>
</xsl:template>




</xsl:stylesheet>

$ saxon9 ol.xml ol.xsl
<?xml version="1.0" encoding="UTF-8"?>
:2
:2
:1
:1

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