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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Replace an attribute
Hi there, I am new to xslt but I have an xml file in the following format <root> <file name=3D"c:\blah\blah\class.java"> <error line=3D"1" message=3D"Parameter status should be final"/> </file> </root> I would like to be able to replace the name attribute of the file = element in the original file and leave the rest of the file intact, then = pass the results to a different stylesheet. The first step is simply replacing the attribute I had a look at the replace function and tried something like this <xsl:value-of select=3D'replace(@name,"c:\blah\blah\*","files")'/> Unfortunately that seemed to have no effect at all. I must be missing something painfully obvious Any advice or suggestions are welcomed, perhaps another function should = be used but replace sure seems right Thanks Sean
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