Re: displaying a list in a multi-column table
On 25/01/2008, John Snelson <john.snelson@xxxxxxxxxx> wrote: > Hi Michael, > > You've got a grouping problem - which is easier to solve in XSLT 2.0. > You can use something like this: > > <table> > <xsl:for-each-group select="word" group-by="position() mod 4"> > <tr> > <xsl:for-each select="current-group()"> > <td><xsl:value-of select="."/></td> > </xsl:for-each> > </tr> > </xsl:for-each-group> > </table> That's a nice way of grouping... something that I hadn't considered until now - but in this case will break the alphabetical ordering won't it? (you'll get positions 1, 5, 9 etc in the first column) -- Andrew Welch http://andrewjwelch.com Kernow: http://kernowforsaxon.sf.net/
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