Re: XSLT 1.0 and XSLT 2.0 differences in position()?

<xsl:if test="position( ) !=last( )">, </xsl:if>
<xsl:if test="position( )=last()-1">and </xsl:if>


If you are processing every item then clearly (if there are more 1
items) this will make ", and" as on the last but one iteration
position()!=last(0 so you get a , and it is equal to last()-1 so you get
and as well.

If you only want , in the cases before you do and, not overlapping
cases, then code it that way:


<xsl:if test="position( ) &lt; last( )-1">, </xsl:if>
<xsl:if test="position( )=last()-1">and </xsl:if>

the difference between xslt 1 and 2 is that in xslt 1 you are probably
just processing the items in positions 2,4,6,... with intervening items
being white space, that;s a dangerous practice (if you have any white
space after the last item the "and" will come in the wrong place.

xslt 2 (if you have a suitable dtd/schema) will autmatically throw away
the white space.

If you are using position() it's safest to explictly make sure just the
right nodes are select by going for example apply-templates
select="xyz"/. rather than <xsl:apply-templates/.
David

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