Re: Find the node with maximum elements

This solution is nice. But if the OP wants to do something else with
the result (not just printing the result (sequence), as this solution
demonstrates), then I think xsl:for-each loop will be necessary.

<xsl:template match="/">
  <xsl:for-each select="/Sample/*[count(Car)=max(/Sample/*/count(Car))]">
    <xsl:value-of select="name(.)"/>
    <xsl:text>
</xsl:text>
  </xsl:for-each>
</xsl:template>

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