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Hi,
The XML I have below, I have been successfully using the id function to generate the output to print out "Technology" as the topic of the book. However, I would also like to print out the other one, "Resources" with the display of the result. Since I marked the id only as tech, how can I actually get it to print out the preceding or following sibling, without having to mark all the associated ids that go along with it? XSLT: <xsl:template match="book">
<div>
<p>
<span class="booklist">
Topic:
<xsl:call-template name="print"/>
</span>
<xsl:apply-templates/>
</xsl:template><xsl:template name="print"> <xsl:choose>
<xsl:when test="count(ancestor::subject) > 1 ">
<xsl:if test="preceding-sibling::subject !=''">
[Also Used for:
<xsl:value-of select="."/>]
</xsl:if>
<xsl:if test="following-sibling::subject !=''">
[Also Used for: <xsl:value-of select="."/>]
</xsl:if>
<xsl:value-of select="id(@topic)"/>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="id(@topic)"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>XML: [---------- The portion is in the header section 6 levels away from the <book> <topicList> <subject xml:id="tech">Technology</subject> <subject xml:id="res">Resource</subject> <subject xml:id="progr">Programming Language</subject> </topicList> --------------] <body> <book topic="tech" rendition="xslt" author="Tennison, Jeni" title="Beginning XSLT"> <p>New York: Apress, 2002.</p> <p>The book serves as an introduction to XSLT based on the examples of a television program set. A resourceful book for those new to the technology.</p> </book> </body> Desired Output: <div><p><span class="booklist">Topic: Technology Resource Programming Language</span> <p>Tenison, Jeni.</span> Beginning XSLT. New York: Apress, 2002. </p> <p>The book serves as an introduction to XSLT based on the examples of a television program set. A resourceful book for those new to the technology.</p> Thanks to those who can help out. Alice
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