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At 2007-09-06 12:24 +1000, Maria Shvedova wrote:
My appologies in advance for the possible incorrect use of terminology, I'm still new to xslt. It sure sounds like you know what you are talking about. I have an xml file that looks like that: ... and the output that I'm trying to achieve is the following: (the grouping needs to occur within each <reference> tag, i.e. I need to get) ... what is happening instead, though, is that elements are being grouped together, so the output that I get is: Yes, because you've used the XSLT 1.0 document-wide grouping method based on keys. here is the stylesheet that I'm using: I'm not sure what you are doing with the <table> element so it is not in my solutions below.
You've implemented a classic application of the Muenchian method, which is just fine for document-wide grouping, but your sub-document grouping can get awkward when using keys. Below I've used a variable-based method for XSLT 1.0 for sub-document grouping. I wasn't exactly sure where you were going with the sorting, so I sorted by @name, and then I sorted the group by title. You can remove what you don't need. Any help would me much appreciated!! its probably obvious, but I've been staring at it for hours.... (The parser we have can work with both xslt 1.0 and 2.0) Then I suggest you switch to XSLT 2.0 which has built-in facilities for grouping. It has greatly simplified my teaching of this requirement. I hope this helps. . . . . . . . . . . . . . Ken
T:\ftemp>type maria.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"><xsl:output indent="yes"/> <xsl:template match="/">
<html>
<body>
<xsl:apply-templates select="export/references/reference"/>
</body>
</html>
</xsl:template><xsl:template match="reference">
<!--put what is being grouped in a variable-->
<xsl:variable name="details" select="detail"/>
<!--walk through the variable-->
<xsl:for-each select="detail">
<xsl:sort select="@name"/>
<!--act on the first in document order-->
<xsl:if test="generate-id(.)=
generate-id($details[@name=current()/@name][1])">
<h2>
<xsl:value-of select="@name"/>
</h2>
<!--revisit all-->
<xsl:for-each select="$details[@name=current()/@name]">
<xsl:sort select="title"/>
<i><xsl:value-of select="title"/></i>
<br/>
</xsl:for-each>
</xsl:if>
</xsl:for-each>
</xsl:template></xsl:stylesheet> T:\ftemp>call xslt maria.xml maria.xsl maria.htm T:\ftemp>type maria.htm <html> <body> <h2>Detail1</h2><i>Detail 1 text</i><br><h2>Detail2</h2><i>Detail2 text</i><br><i>Detail2 text</i><br><h2>Detail1</h2><i>Detail 1 text</i><br><h2>Detail2</h2><i>Detail2 text</i><br><i>Detail2 text</i><br></body> </html> T:\ftemp>type maria2.xsl <?xml version="1.0" encoding="US-ASCII"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output indent="yes"/> <xsl:template match="/">
<html>
<body>
<xsl:apply-templates select="export/references/reference"/>
</body>
</html>
</xsl:template><xsl:template match="reference">
<xsl:for-each-group select="detail" group-by="@name">
<xsl:sort select="@name"/>
<h2>
<xsl:value-of select="@name"/>
</h2>
<xsl:for-each select="current-group()">
<xsl:sort select="title"/>
<i><xsl:value-of select="title"/></i>
<br/>
</xsl:for-each>
</xsl:for-each-group>
</xsl:template></xsl:stylesheet> T:\ftemp>call xslt2 maria.xml maria2.xsl maria2.htm <html> <body> <h2>Detail1</h2><i>Detail 1 text</i><br><h2>Detail2</h2><i>Detail2 text</i><br><i>Detail2 text</i><br><h2>Detail1</h2><i>Detail 1 text</i><br><h2>Detail2</h2><i>Detail2 text</i><br><i>Detail2 text</i><br></body> </html>
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