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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: html as input to xslt
You're right, it's not exactly what I want.
I have this html: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>yellow</title> </head> <body> <div class="navheader"> <p>navheader</p> </div> <div class="something"> <p>something</p> </div> <p>plain</p> </body> </html> I run this transform: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xhtml="http://www.w3.org/1999/xhtml" version="2.0"> <xsl:output method="html" /> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="@*" /> <xsl:apply-templates /> </xsl:copy> </xsl:template> <xsl:template match="//xhtml:div[@class='navheader']"> <xsl:copy-of select="." /> <p>other stuff</p> </xsl:template> </xsl:stylesheet> and I get this output: <html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>yellow</title>
</head>
<body>
<div class="navheader">
<p>navheader</p>
</div>
<p xmlns:xhtml="http://www.w3.org/1999/xhtml" xmlns="">other stuff</p>
<div class="something">
<p>something</p>
</div>
<p>plain</p>
</body>
</html>I'd rather not have the xhtml name stuff in the output. Is there a way around this? Thanks, Lou Owen Rees wrote: --On Tuesday, September 04, 2007 07:07:12 PM -0400 Lou Iorio wrote:
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