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RE: Extract input filename

Subject: RE: Extract input filename
From: "J. S. Rawat" <jrawat@xxxxxxxxxxxxxx>
Date: Thu, 17 May 2007 14:13:57 +0530
RE:  Extract input filename
Thanks for the prompt reply. Would you please let me know about the namesspace value of prefix {xs} as an error is throughing while converting.

Error
undeclared namespace prefix {xs}

At 08:46 AM 5/17/2007 +0100, you wrote:

1. Change this:

<xsl:variable name="filename" select="document('input_meta.xml')" />

to this:

<xsl:param name="meta" as="xs:string" required="yes"/>
<xsl:variable name="filename" select="document($meta)" />

(you might also like to change the name of the variable filename, as it's a
misleading name)

2. Change your command line to

java -jar saxon8.jar input.xml x.xsl meta=input_meta.xml >c.xml

Michael Kay
http://www.saxonica.com/


> I have no idea about to extract input filename by passing > argument in command line. In the below examples, I don't want > to hardcode "input_meta.xml". > > Input files > 1. input.xml > 2. input_meta.xml > > command line > java -jar saxon8.jar input.xml x.xsl >c.xml > > Stylesheet > <xsl:variable name="filename" select="document('input_meta.xml')" /> > <xsl:template match="/"> > <doi> > <xsl:copy-of select="$filename/doi/text()" /> > </doi> > </xsl:template> > > Thanks in advance. > JSR

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