Re: [xsl] finding position() in xpath 1.0

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Subject: Re: finding position() in xpath 1.0
From: Frank Marent <frank.marent@xxxxxxxxxxx>
Date: Mon, 19 Mar 2007 14:15:00 +0100

david, abel

I think I mis read your requirement. the code I posted works so long as there is at most one node with test="yes. If you have multiple such nodes and need to select the preceding cousin of all of them, Then...

//CELL[@test='yes']/../preceding-sibling::ROW[1]/CELL[position() =count(../following-sibling::ROW[1]/CELL[@test='yes']/preceding- sibling::CELL)+1]

it's always a good feeling among xml-giants... i was posting the point you've detected yourself - and abel. your statement reads for me like:

//CELL[@test='yes']magic()/but()/it()/works()/halleluja()/preceding- sibling::CELL)+1]

thank you very much,
it works great

frank

Current Thread

Re: finding position() in xpath 1.0, (continued)
- David Carlisle - 19 Mar 2007 12:54:24 -0000
  - David Carlisle - 19 Mar 2007 13:08:34 -0000
    - Frank Marent - 19 Mar 2007 13:15:49 -0000 <=
    - Abel Braaksma - 19 Mar 2007 13:24:44 -0000
    - Abel Braaksma - 19 Mar 2007 13:50:27 -0000
    - Frank Marent - 19 Mar 2007 13:59:39 -0000
    - Abel Braaksma - 19 Mar 2007 14:04:26 -0000

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Re: finding position() in xpa, David Carlisle	Thread	Re: finding position() in xpa, Abel Braaksma
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