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Jeff Sese wrote:
Hi Jeff, David Carlisle already showed you how to do it in XSLT 1.0 with mode switching. I don't know if you have the possibility to use XSLT 2.0, but here's a solution that does the same in XSLT 2.0, with the help of a little function that turns any range of attributes into a hierarchical node list, making it easier to use with matching templates. It's perhaps a bit non-conventional, but it keeps your code pretty tight. Output from your source is equal to the requested output. Happy coding! -- Abel Braaksma http://abelleba.metacarpus.com
<xsl:output indent="yes" /> <xsl:template match="inline"> <xsl:copy> <xsl:apply-templates select="f:attr-to-nodes-hier(attribute::*, text())" /> </xsl:copy> </xsl:template> <!-- result from f:attr-to-nodes-hier --> <xsl:template match="attr"> <emphasis format="{@value}"> <xsl:apply-templates select="node()" /> </emphasis> </xsl:template> <!-- result from f:attr-to-nodes-hier --> <xsl:template match="attr[@name = 'vertical-alignment']"> <superscript> <xsl:apply-templates select="node()" /> </superscript> </xsl:template> <xsl:function name="f:attr-to-nodes-hier" as="node()*"> <xsl:param name="attributes" as="attribute()*" /> <xsl:param name="text" as="text()" /> <xsl:if test="$attributes"> <attr name="{$attributes[1]/name()}" value="{$attributes[1]}"> <xsl:copy-of select="f:attr-to-nodes-hier($attributes[position() > 1], $text)" /> </attr> </xsl:if> <xsl:if test="empty($attributes)"> <xsl:sequence select="$text" /> </xsl:if> </xsl:function> </xsl:stylesheet>
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