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Re: XSLT/XPath Question (Grouping Authors by First Ch

Subject: Re: XSLT/XPath Question (Grouping Authors by First Character of Last Name)
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Sun, 04 Mar 2007 16:00:21 -0500
Re:  XSLT/XPath Question (Grouping Authors by First  Ch
At 2007-03-04 12:41 -0800, Kevin Grover wrote:
Excellent! That's exactly what I was trying to achieve. Thanks.

It also seems that this may have answered my other question: about
saving the list of letters so I can iterate over them later (to make
links to the TOC entries.  It looks like I can just take the main
for-each loop and save that code to a variable.  I'll play with it.

I guess I need to play with the <xsl:key/>'s some more.  The code does
not seem obvious to me at all....

Sorry 'bout that ... little time to document when doing volunteer work.

There is a discussion of the XSL key facility in section 3.4 of the free developer resources section of our web site.

Thankfully, the concepts are easy once you hear how they work.

On 3/3/07, G. Ken Holman <gkholman@xxxxxxxxxxxxxxxxxxxx> wrote:
t:\>type grover.xsl
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text"/>

Declare a lookup table with all authors in the left column and the first letter of their file-as string in the right column:

   <xsl:key name="alet" match="author"

<xsl:template match="/">

Looking at all authors, keep only those in the current node list that are the first in document order ... checking the order by checking the unique identifier for the current node against the unique identifier for the first one found using the key() lookup feature:

<xsl:for-each select="*/author[generate-id(.)=

      <xsl:value-of select="substring(name/@file-as,1,1)"/>

Look up all authors that have the same first letter as the author being processed:

      <xsl:for-each select="key('alet',substring(name/@file-as,1,1))">
        <xsl:value-of select="name/@file-as"/>

I hope this helps ... good luck in your work with XSL.

. . . . . . . . . . . Ken

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