If there's no template in your stylesheet that matches a given element, then
the default template kicks in: this outputs the text of the element (without
any tags). Change the default by including

<xsl:template match="*"/>

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Ramona Krickan [mailto:ramona.krickan@xxxxxxxxxx] 
> Sent: 08 March 2007 14:52
> To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'
> Subject:  XSLT Output contains the unwanted content of 
> all elements as text
> 
> Hi,
> 
> I got a Problem with my transformation output. My xslt doc 
> does the correct transformation but in my output document I 
> not only get the expected transformation but also the 
> text-content of all the other elements from my source 
> document. I don't undestand why. Could somebody please help me?
> 
> Here my xslt:
> <xsl:stylesheet version="2.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> xmlns:zoo="http://example.com/ns">
> <xsl:template match="element(zoo:country)"> <xsl:variable 
> name="countryCode" select="."/> <xsl:value-of select="if 
> ($countryCode='CH') then ('AT') else ($countryCode)" /> 
> </xsl:template> </xsl:stylesheet> 
> 
> My input xml:
> <zoo:address xmlns:zoo="http://example.com/ns">
> <zoo:street>Strasse</zoo:street>
> <zoo:country>CH</zoo:country>
> </zoo:address> 
> 
> output document:
> Strasse /*this is unexpected*/
> AT
> 
> Thanks in advance for any help!
> 
> Ramona Krickan
> 
> zooplus AG
> Eichenweg 4a
> 85774 Unterfoehring
> Germany
> Tel +49.89.95 00 6-194
> Fax +49.89.95 00 6-500
> mailto:ramona.krickan@xxxxxxxxxx
> http://www.zooplus.de