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Rachel D. Basse wrote:
Hi Rachel, It's a classic, and every now and then, I do it wrongly still (check the archives, I have once or twice asked about the same question). The function position() (you don't need to put "fn:" in front of it) returns the position of the context node. The context changes within the XPath expression to each node it is evaluating. Thus, the expression ('a', 'b')[position()] a) will test the first item in the sequence 'a' for the predicate [position()] which evaluates to the predicate [1], which is short for [position() = 1], which will return true because the current position is 1. b) will test the second item in the sequence 'b' for the predicate [position()] which evaluates to the predicate [2], which is short for [position() = 2], which will return true because the current position is 2 (we are at the second item, 'b', remember). As it comes, the following: some-node[position()] will always evaluate to true, and (some-sequence)[position()] will always return the whole sequence, because each separate item will always have the position in the sequence that equals the result of the predicate [position()]. What you want is the following: <xsl:variable name="pos" select="position()" />
<xsl:sequence select="('a', 'b')[$pos]" />HTH, Cheers, -- Abel Braaksma http://www.nuntia.nl
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