Subject: RE: Using xsl:sort to sort negative values
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Wed, 21 Feb 2007 09:33:49 -0000
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> Can anyone tell why the code below will not work?
>
> <xsl:sort select="data" data-type="number"/>
>
> I am trying to sort numeric data that contains negative
> values but the order seems to be wrong
>
> <xml>
> <data>22</data>
> <data>2</data>
> <data>-5</data>
> <data>42</data>
> <data>0</data>
> <data>-1</data>
> <data>0</data>
> </xml>
If data selects anything, then it will select 7 child elements of <xml>, and
a sort key consisting of a sequence of 7 elements is unlikely to be useful.
Chances are you want
<xsl:for-each select="data">
<xsl:sort select="." data-type="number"/>
Incidentally, element names beginning with "xml" are reserved for future
standardization, therefore best avoided.
Michael Kay
http://www.saxonica.com/
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