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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Dynamic numbering of lists in xslt
 <xsl:number /> <!-- will only count the matches consecutively --> You are right, of course. Using position(), you can change this behavior through the apply-templates. Using the input from the OP, and my approach, the following is a way to do it (using xslt 2 for ease of use and not needing an input doc, call it on itself) <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output indent="yes"/> <xsl:variable name="source"> <chapter1> <section>first section</section> </chapter1> <chapter1> <section>second section</section> </chapter1> <chapter1> <section>third section</section> </chapter1> <chapter1> <section>fourth section</section> </chapter1> </xsl:variable> <xsl:template match="/"> <xsl:apply-templates select="$source/chapter1[not(section = 'second section')]" /> </xsl:template> <xsl:template match="chapter1"> <chap> <xsl:value-of select="concat(position(), '. ', section)" /> </chap> </xsl:template> </xsl:stylesheet> Output: <chap>1. first section</chap> <chap>2. third section</chap> <chap>3. fourth section</chap> However, if the select-statement becomes more complex, other approaches may be better (not meaning xsl:choose). In addition, if XSLT 2.0 were an option, the select-attribute could be used to achieve the same goal. If Saxon extensions can be used, an easy (but unwanted) quick fix is to use saxon's assignable variables. -- Abel 
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