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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Generating a unique listing of elements from multi
Your input wasn't well formed but after fixing that, i think this does
what you want. Th e"uniqueness" aspect is automatic given xpath1's node
set semantics as sets never have repeated values.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="c" match="country" use="@id"/>
<xsl:key name="cg" match="countryGroup" use="@groupID"/>
<xsl:template match="data">
<xsl:apply-templates select="businesses/business"/>
</xsl:template>
<xsl:template match="business">
<xsl:text> </xsl:text>
<xsl:value-of select="name"/>
<xsl:text>: </xsl:text>
<xsl:for-each select="key('c',key('cg',countryGroup/@included)/country/@included)">
<xsl:value-of select="."/>
<xsl:text> </xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
$ saxon gm.xml gm.xsl
<?xml version="1.0" encoding="utf-8"?>
Acme: United States Mexico
Another Acme: Canada Mexico
David
oops I just use saxon on the command line, silly me:-)
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