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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Linebreak problem
How do I make a linebreak in xsl-fo ? This is what I've tried. XML: <letter> <text>I really need a linebreak in this line <br/> because I need to see how it' done</text> </letter> XSL: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" version="1.0"> <xsl:template match="/"> <fo:root xmlns:fo="http://www.w3.org/1999/XSL/Format"> <fo:layout-master-set> <fo:simple-page-master master-name="frame" page-height="297mm" page-width="209mm" margin-left="0mm" margin-right="0mm"> <fo:region-body region-name="frame-body"/> </fo:simple-page-master> </fo:layout-master-set> <fo:page-sequence master-reference="frame"> <fo:flow flow-name="frame-body" font-family="Times"> <fo:block> <xsl:value-of select="letter/text"/> </fo:block> </fo:flow> </fo:page-sequence> </fo:root> </xsl:template> <xsl:template match="br">
<fo:block/>
<xsl:apply-templates/>
</xsl:template></xsl:stylesheet> This doesn't work.....why ? Asbjxrn
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