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RE: XPath attribute expression

Subject: RE: XPath attribute expression
From: "Hintz, David L" <dlh@xxxxxxx>
Date: Tue, 19 Dec 2006 10:20:50 -0500
attribute xpath
I should have noted that this is not an XSLT application.  So, I need a
pure XPath expression -- probably XPath 1.0.  Any ideas?

-----Original Message-----
From: Alexey Nickolaenkov [mailto:nikolaenkov@xxxxxxxxxxxx]
Sent: Tuesday, December 19, 2006 1:29 AM
To: Hintz, David L
Subject: Re:  XPath attribute expression

Tuesday, December 19, 2006, 2:27:52 AM, you wrote:

HDL> Assume that my document has this structure:

HDL> <topLevel>
HDL>    <ents>
HDL>       <ent name="abc"><value>test1</value></ent>
HDL>       <ent name="def"><value>test2</value></ent>
HDL>    </ents>
HDL> .
HDL> .
HDL> .
HDL> <para>This is a <entRef name="def"/>.</para>

HDL> What XPath expression can I use in context of this <entRef> element
HDL> reference the content of the <value> element that matches the <ent>
HDL> attribute (as shown above).  I've gotten this far:

HDL> /topLevel/ents/ent[@name]/value

HDL> But, that always returns the first value.  Somehow I need to test
HDL> that equals the "name" of the current tag.

I think that problem is not in XPath but in templates. I suppose
something like that will suit for you:

   <xsl:key name="ents-by-name" use="@name" match="//ents/ent"/>

   <xsl:template match="topLevel">
            <meta http-equiv="Content-Type" content="text/html;
            <xsl:apply-templates select="page"/>

   <xsl:template match="para">
      <p><xsl:apply-templates select="@*|node()"/></p>

   <xsl:template match="entRef">
      <xsl:variable name="ent-name" select="key('ents-by-name',

            <xsl:when test="$ent-name">
               <xsl:value-of select="$ent-name"/>

               <xsl:text/>Undefined ent

Alexey                            mailto:alexey.nikolaenkov@xxxxxxxxxxxx

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