Subject: Re: Referring to stylesheet itself, possible in XSLT 1.0, but how in XSLT 2.0?
From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx>
Date: Tue, 17 Oct 2006 14:45:21 +0100
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On 10/17/06, Abel Braaksma <abel.online@xxxxxxxxx> wrote:
David Carlisle wrote:
> Incidentally, why do you want to use document('')??
No reason in particular, other than getting the stylesheet that is
currently being executed. I tried all sorts of ideas and combinations of
ideas, but the result is simple: it cannot be done once you have the
xsl:stylesheet offset to some directory where your current stylesheet
does not reside.
So, if your stylesheet uses something like this:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0" xml:base="../..">
but is itself not at location "../..", all bets are off for getting the
location of the current stylesheet.
Instead of using xml:base why not just create a parameter $path and
then modify all of your paths in the stylesheet to contain that
parameter, eg:
<xsl:param name="path" select="'../../'" as="xs:string"/>
and
href="{$path}existingpath"
cheers
andrew
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