<xsl:template match="/address">
   <address>
     <xsl:apply-templates />
   </address>
 </xsl:template>

 <xsl:template match="*[../self::address]">
   <xsl:element name="{concat('US_', local-name())}">
     <xsl:value-of select="." />
   </xsl:element>
 </xsl:template>

<address>
 <streetAddress>123 First Street</streetAddress>
 <city>Sometown</city>
 <state>CA</state>
 <zip>12345</zip>
 <province/>
 <country>USA</country>
</address>

<?xml version="1.0" encoding="UTF-8"?>
<address>
  <US_streetAddress>123 First Street</US_streetAddress>
  <US_city>Sometown</US_city>
  <US_state>CA</US_state>
  <US_zip>12345</US_zip>
  <US_province/>
  <US_country>USA</US_country>
</address>

Hi All,

I have the following structure in my XML and I want to transform this
all "address" node content to prefix with "US".
Please let me how to create the XSL template for the given input.

Input
  <address>
   <streetAddress>123 First Street</streetAddress>
     <city>Sometown</city>
     <state>CA</state>
     <zip>12345</zip>
     <province />
     <country>USA</country>
  </address>

output
  <address>
   <US_streetAddress>123 First Street</US_streetAddress>
     <US_city>Sometown</US_city>
     <US_state>CA<US_/state>
     <US_zip>12345</US_zip>
     <US_province />
     <US_country>USA</US_country>
  </address>

I do not know how to create the XSL for it to transform.

Thanks for your help.

Regards,
Senthil

--
Regards,
Mukul Gandhi