Subject: Re: Relationships in for-each statement
From: "Bob Portnell" <simply.bobp@xxxxxxxxx>
Date: Thu, 7 Sep 2006 15:44:08 -0700
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First, it doesn't look to me like you need that xsl:if test at all.
As on other occasions, if no such nodes exist, a for-each instruction
won't select any to operate on.
:-) "While we were in a commercial break," that xsl:if test lets me
know I need to output a proper header for the group of items to
follow.
So...
<xsl:for-each select="$monster-path-perhaps-best-bound-to-a-variable">
Yeah, I saw that from David. I'm very excited about that, for more
than one reason.
Thanks! (And thanks, again, David!)
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