Hi David,

The XSL I have used is given below.

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="no"/>

  <xsl:template match="elem">
   <xsl:text>&#10;Elem Id, News Details&#10;</xsl:text>
   <xsl:value-of select="@id"/>
   <xsl:text>, "</xsl:text>
   <xsl:apply-templates select="text/*"/>
   <xsl:text>"</xsl:text>
  </xsl:template>


   <xsl:template match="text()">
    <xsl:call-template name="transformXMLString">
      <xsl:with-param name="StringToTransform" select="."/>
    </xsl:call-template>
  </xsl:template>

  <xsl:template  name="transformXMLString">
   <xsl:param name="StringToTransform" select="."/>
   <xsl:value-of
select="translate($StringToTransform,'&#10;&quot;','@!')"/>
  </xsl:template>
</xsl:stylesheet>

I am getting the following output.


Elem Id, News Details
1234, "    This is some data          This is some special characters
&lt;AHLN.AS&gt;     A group of students have gone to picnic.          **
This is another special tag@     @ @  "

I am not able to retain the HTML tags. The output should be as follows.

Elem Id, News Details
1234, "<p>    This is some data </p><br><p></p><br><p>    This is some
special characters &lt;AHLN.AS&gt; </p><br><p>    A group of students
have gone to picnic. </p><br><p>     </p><br><PRE>    ** This is another
special tag<br></PRE></text><br></elem>"

Line breaks should be replaced by <br> and HTML tags retained as it is.
It should be CSV like output.

Thanks & Regards,
Ambika Prasad Das


-----Original Message-----
From: David Carlisle [mailto:davidc@xxxxxxxxx]
Sent: Friday, September 08, 2006 8:37 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  Replace new lines by <br> and double quote with
special char: Problem retaining HTML tags



> I have tried David's code. But the output is required in a particular
> format since the output is the input for another application

In my reply I said

> You just need to fill in the replace template and templates for any
> elements that you need to process by somthing other than copy.

which in this case means adding a template for elem
something like this

  <xsl:template match="elem">
   <xsl:text>&#10;Elem Id, News Details&#10;</xsl:text>
   <xsl:value-of select="@id"/>
   <xsl:text>, "</xsl:text>
   <xsl:apply-templates select="text/*"/>
   <xsl:text>"</xsl:text>
  </xsl:template>

and a template for the replace, something like this (which isnt the
replace you wanted but fits on one line so does as an example)

  <xsl:template  name="transformXMLString">
   <xsl:param name="StringToTransform" select="."/>
   <xsl:value-of
select="translate($StringToTransform,'&#10;&quot;','@!')"/>
  </xsl:template>

Then it appears that you want the line breaks in all elements (eg
<pre>). changing, not just those below <p> so change
  <xsl:template match="p//text()">
to
  <xsl:template match="text()">
so thattemplate matches all text nodes.

Then the code that I posted before on the input that you just posted
produces the following which looks fairly close to what you want to me:

 saxon grumble.xml grumble.xsl

Elem Id, News Details
1234, "<p>    This is some data </p><p>     </p><p>    This is some
special characters &lt;AHLN.AS&gt; </p><p>    A group of students have
gone to picnic. </p><p>     </p><PRE>    ** This is another special tag@
@ @  </PRE>"