Re: more elegant way of doing this? (very simple)

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Subject: Re: more elegant way of doing this? (very simple)
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Wed, 16 Aug 2006 12:54:11 -0400

At 2006-08-16 12:42 -0400, Steve wrote:

Summing up 3 specifically named nodes under Records/Record and summing
them only if they are numbers.

Current XSL===>

sum(Records/Record/*[name(.) = 'AContribution' and number(.) =
number(.) or name(.) = 'BContribution' and number(.) = number(.) or
name(.) = 'CContribution' and number(.) = number(.)])

The following would be more compact:

sum( ( Records/Record/AContribution | Records/Record/BContribution
     | Records/Record/CContribution )[number(.)=number(.)] )

It is not namespace-safe to use name(.).

I'm just trying to reduce redundancy.


You don't say *where* you want to reduce
redundancy ... the above syntactically reduces
your expression ... I cannot comment on the speed
as that would be dependent on your processor so I
don't think the question can be answered in that way.

I hope this helps.

. . . . . . . . . . . Ken

--
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Current Thread
more elegant way of doing this? (very simple) Steve - 16 Aug 2006 16:42:56 -0000 David Carlisle - 16 Aug 2006 16:53:22 -0000 Steve - 16 Aug 2006 16:56:58 -0000 Message not available G. Ken Holman - 16 Aug 2006 16:55:14 -0000 <=

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