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This is my first attempt at this, so I want to make sure there's not a
better way to do it. I'm setting up my XSL stylesheet by incorporating
my css styles right in it. (If I'm not explaining that well, here's a snip)
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="/"> <xsl:for-each select="//guest"> <xsl:apply-templates select="name"/> </xsl:for-each> </xsl:template> <xsl:template match="name"> <html> <head> <style type="text/css"> .sidelinks { font-size: 8pt; color: #AA7700; text-decoration: none } #mainright { position: absolute; left: 300px; top:145px; width:500px; font-weight: bold; line-height:1.25; padding: 10px; } </style> </head> <body> <div id="mainright"> <div class="sidelinks">Name: <xsl:value-of select='.'/><br /> Department: <xsl:apply-templates select="../location"/><br /> Website: <xsl:apply-templates select="../website"/><br /> Email: <xsl:apply-templates select="../email"/><br /> Comment: <xsl:apply-templates select="../comment"/><hr /> </div> </div> </body> </html> </xsl:template> </xsl:stylesheet> My question is - is this the best way to do it? Can I add a link to an external style sheet in the XSL? Thanks in advance! Michelle -- "Every worthwhile accomplishment, big or little, has its stages of drudgery and triumph; a beginning, a struggle and a victory." --Mahatma Gandhi ***************************** Michelle Tarby Director of Web Services Information Technology Le Moyne College http://www.lemoyne.edu tarbymm@xxxxxxxxxxx
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