You haven't shown your source code so it's hard to see where you're going
wrong.

If you do

<xsl:apply-templates select="section, ref, ack, app"/>

then the sections will be processed in that order, and position() used
within the relevant templates will give you consecutive numbering. Also
count(section|ref|ack|app) will give you the right total.

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Karl [mailto:call14@xxxxxxxxx] 
> Sent: 20 July 2006 10:50
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Is there any multiple if exression (not 
> xsl:if) available in xpath/xslt2 ?
> 
> I have an xml having some 'n' number of <section>'s + 3 
> OPTIONAL elemts <ref>, <ack> and <app>, which must appear in 
> that order. 
> Though my actual reqmt is to generate html pages in that 
> names with links from every page, what in essence i would 
> prefer to get is
> 
> 1. section 1
> 2. section 2
> ...
> n. section n 
> n+1 ref
> n+2 ack
> n+3 app
> 
> The problem is if ref is not present, it will be n. section n
> n+1 ack
> n+2 app
> 
> or if ack not there
> n+1 ref
> n+2 app
> 
> and the combination can be anything as those 3 elemts are 
> optional. I can have many <xsl:if>s to find and get what i 
> want. But is there a elegant solution or expression (can be 
> even xslt 2/xpath 2) that will reduce multiple if stmts?
> 
> Also, i need to count Total num of pages. Is there any expr 
> like Total pages = <xsl:value of select"count(//section) + 
> if(ref) add 1 + if (ack) add 1 + if(app) add 1"/> 
> 
> Thanks
> karl
> 
> 
> 		
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