Re: Moving (promoting) XML elements through XSL

Thanks for your input, David!  I think I made your suggested changes
correctly, but my output hasn't changed. The indexterm element still
doesn't appear in my output XML doc.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
	<xsl:output indent="yes"/>
	<xsl:template match="/topic">
		<xsl:copy>
			<prolog>
				<metadata>
					<keywords>
						<xsl:copy-of select="title/indexterm"/>
					</keywords>
				</metadata>
			</prolog>
			<xsl:apply-templates select="@*|node()"/>
		</xsl:copy>
	</xsl:template>
	<xsl:template match="indexterm"/>
	<xsl:template match="@*|node()">
		<xsl:copy>
			<xsl:apply-templates select="@*|node()"/>
		</xsl:copy>
	</xsl:template>
</xsl:stylesheet>

Regards,
Mark

you have two templates matching
   <xsl:template match="@*|node()">
   <xsl:template match="@*|node()">
which is an errror (even though they are the same template) a system may
ignore the first or it may stop and reject the stylesheet.

           <xsl:copy-of select="/title/indexterm"/>
This copies nothing, you meant
           <xsl:copy-of select="title/indexterm"/>
ie the indexterm grandchild of the current node (topic).
/title would select the title child element of teh root but there is no
such element, the element of  / is topic.

> (I haven't figured gotten as far as wrapping
> the indexterm elements yet):

that's easy
<keywords>
           <xsl:copy-of select="title/indexterm"/>
</keywords>

David

Mark Peters
Senior Technical Writer
Saba Software