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RE: >Subject: RE: node comparision for equality:
Subject: RE: >Subject: RE: node comparision for equality: Message-ID: <448F3BD6.605|
From: "uppaluri satyaprasad" <uppaluris@xxxxxxxxxxx>
Date: Tue, 20 Jun 2006 01:09:52 -0400
uppaluri satyaprasad wrote:
however i need to also test if
BusPartnerCodeValue (i.e. D06001 here) and BusPartnerCodeTypeCode (i.e.
00003) are equal in two nodes within BPPLCode.
if these two values are equal, the BPPLCode nodes are equal and i shall
process only one node.
we can ignore ProductLevel/ProductLevelCode here.
This looks like the "select distinct" problem, which you can solve
with an approach described here:
Use grouping by content, using
as key indicator.
(unfortunately, http://jenitennison.com/xslt/unique.xml is a stub).
Thank you for your help.
I managed to get my problem fixed using Muenchian method as advised
I have one more related question. i want to find no of those
distinct nodes (same business rule as above)
when I try to use the keys it will give me the count of the nodes in
the entire document.
however i need to find the count of the unique nodes inside each
thanks in advance
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