RE: xsl:apply-templates and select option
David, Thanks for your reply. If I understand you correctly, here is what I need to do: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:els="http://www.consumerdirect.com/namespaces"> <xsl:import href="copy.xslt"/> <xsl:include href="ELSTranslator.xslt"/> <xsl:import href="ELSGrouper.xslt"/> </xsl:stylesheet> Where translator substitutes the node names and grouper creates groups. However, I am not able to get that to work. In the above order I get the substitution but no grouping. Any ideas what may be wrong?! Thanks. -r -----Original Message----- From: David Carlisle [mailto:davidc@xxxxxxxxx] Sent: Friday, June 02, 2006 7:20 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: xsl:apply-templates and select option > I need to have grouper process the result of sub template, and its not > happening. It instead tries to parse the original xml doc. In pure XSLT 1 the only way to process the result of a template is to have two stylesheets, first process to an intermediate document, then process that document with a second stylesheet. Most systems offer a node-set() extension function which allows you to convert the result of applying templates (a result tree fragment variable) into a node set (which can then be used as the select on an apply templates). Or you can use XSLT2 where result tree fragments and node sets are the same thing, and so no function is needed to coerce between them. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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