Re: for-each loop question
There is a good explanation about Piez method at http://www.dpawson.co.uk/xsl/sect2/muench.html (topic number 7). //node() is one node-set which I mentioned. As mentioned in the FAQ, you can use the expression / | //node() | //@* | //namespace::* to increase the number of nodes. Regards, Mukul On 3/31/06, Mukul Gandhi <gandhi.mukul@xxxxxxxxx> wrote: > The Piez method would work only if the number of iterations you want > to perform are less than or equal to count(//node()). > > The general purpose methods will be the XSLT 2.0 technique and > recursive technique as Andrew has suggested. > > Regards, > Mukul > > On 3/31/06, andrew welch <andrew.j.welch@xxxxxxxxx> wrote: > > On 3/31/06, Khorasani, Houman <Houman.Khorasani@xxxxxxxxxxxx> wrote: > > > Hello everyone, > > > > > > I got a "for-each" problem here and am wondering if you could solve it: > > > > > > This is the input XML file: > > > > > > <A> > > > <B> > > > <Product Quantity="5" Code="A75570" Description="REMINDER CALL - > > > WA"/> > > > </B> > > > </A> > > > > > > > > > I am interested in the Quantity attribute of 5. > > > > > > I would like to run the "for-each" loop about 5 times: > > > > > > <xsl:variable name="loop" select=" A/B/Product[@Quantity]"/> > > > <xsl:for-each select="$loop"> > > > <xsl:call-template name="xxx"> > > > > > > </xsl:call-template> > > > </xsl:for-each> > > > > > > > > > Would that be possible like this? > > > > No, as the context is a single <Product> node... > > > > Doing what you are after is simple is XSLT 2.0, you could just use > > select="1 to $quantity". > > > > In 1.0 it's a lot harder, you will need to write a recursive named > > template that calls itself decrementing the count with each call, or > > use the Piez 'hack' of select="$someElementList[position() <= 5]" > > > > As you haven't said if you can use 2.0 or not, I won't expand on the > > 1.0 solutions until then :) > > > > cheers > > andrew
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