RE: Divide to pages

Maybe this helps:
<xsl:param name='items-by-page' select='5'/>

... Number of pages:
<xsl:variable name='pages' select='floor(count(item) div $items-by-page)'/>

... With a recursive loop, with params: counter from 1 to pages
<xsl:if test="position() = ($items-by-page*$counter)">EOP</xsl:if>


-----Original Message-----
From: Paull [mailto:paullus4mlist@xxxxxxxxx] 
Sent: Wednesday, April 05, 2006 8:08 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Divide to pages

Hello All,
following xml:
<data>
<item name="1" id="i1">v1</item>
<item name="2" id="i1">v2</item>
<item name="3" id="i1">v1</item>
<item name="4" id="i1">v1</item>
<item name="5" id="i1">v2</item>
<item name="6" id="i1">v1</item>
<item name="7" id="i1">v1</item>
<item name="8" id="i1">v2</item>
<item name="9" id="i1">v1</item>

<item name="10" id="i2">v2</item>
<item name="11" id="i2">v2</item>
<item name="12" id="i2">v2</item>


<group name="g1" id="i1"/>
<group name="g2" id="i2"/>
</data>
should be transformed to the xml, where items are grouped by id, and 
divided to pages whith 5 items per page. Result should be like following:
g1
1. i1v1
2. i1v2
3. i1v1
4. i1v1
5. i1v2
EOP
1. i1v1
2. i1v1
3. i1v2
4. i1v1
g2
5. i2v2
EOP
1. i2v2
2. i2v2

I can group it, but how to divide for pages - no idea ...
WBR, Paull