Re: Transform XML to DXL using XSLT

Hi,

Thanks Gurus for your help.
I am really new to XSL so gets stuck in simple problems.

How can I modify the xsl program given by Michael and Florent if the
Document A is
<eapqp:ItemList>
         <eapqp:Level>Level 1</eapqp:Level>
      <eapqp:PartNumber>987654321</eapqp:PartNumber>
</eapqp:ItemList>

I tried by changing the xslt by

<xsl:template match="eapqp:Level">
   <item name="Level"><text><xsl:value-of select="."/></item>
</xsl:template>

But it giving me error as illegal prefix.
Please suggest a solution.


Cheers,
Rob


On 3/2/06, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> > Now I am stuck with a new problem and I am not able to find
> > any solution for it.
>
> If this is a new problem, then I wonder what problems you've been tackling
> until now. This is about as classic a one-to-one transformation as they
> come.
> >
> > I want to use XSLT to transform XML file to DXL (Domino XML) file. Dxl
> > file is also a xml file used by Lotus Notes.
> > For example what could be the xslt for converting document A
> > into document B.
>
> <xsl:template match="ItemList">
> <documents>
>   <document>
>     <xsl:apply-templates/>
>   </document>
> </documents>
> </xsl:template>
>
> <xsl:template match="Level">
>   <item name="Level"><text><xsl:value-of select="."/></item>
> </xsl:template>
>
> <xsl:template match="PartNumber">
>   <item name="PartNumber"><text><xsl:value-of select="."/></item>
> </xsl:template>
>
> Michael Kay
> http://www.saxonica.com/
>
> >
> > Document A:
> >
> > <ItemList>
> >         <Level>Level 1</Level>
> >         <PartNumber>987654321</PartNumber>
> > </ItemList>
> >
> > Document B:
> >
> > <documents>
> >     <document>
> >         <item name="Level"><text>Level 1</text></item>
> >         <item name="PartNumber"><text>987654321</text></item>
> >     </document>
> > </documents>
> >
> > Thanks in advance.
> >
> > Cheers,
> > Rob