Re: Sudoku - A solution in XSLT 2
> This is a great idea :) seems so obvious now.... not sure if the table is better than just working out the group number $groups[$x] is 1+ 3* (($x - 1) idiv 27) + ((($x -1) idiv 3 )mod 3) groups[$x] probably takes time proportional to $x (unless Saxon does something clever there) but the expression is presumably more or less constant time if you stay within machine integer range, but since the board is only 81 entries rather than thousands of entries, the limiting behaviour isn't really relevant and it's just a matter of trying it out in the particular implementation I suppose. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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