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Re: xsl:for - Only for existing nodes, how?

Subject: Re: xsl:for - Only for existing nodes, how?
From: "Liron" <magilam@xxxxxxxxxxxxxxxx>
Date: Tue, 21 Feb 2006 18:16:57 +0100
david liron
Hi David,

Thank you again for your reply, you helped a lot


----- Original Message ----- From: "David Carlisle" <davidc@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, February 21, 2006 6:10 PM
Subject: Re: xsl:for - Only for existing nodes, how?

Wouldn't it act just the same? I'm talking in a performance sense.

No, your solution tests that there is an item1 and if so outputs item1 and item2 (the latter may be empty) mine checked that there was an item 1 and an item2.

If you have


your solution would output x but mine would output nothing as there is
no item2. I can't say which you need though.


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