ancestor axis ordering (again...)

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Subject: ancestor axis ordering (again...)
From: Joern Nettingsmeier <nettings@xxxxxxxxxxxxxxxxxxxxxx>
Date: Mon, 27 Feb 2006 14:43:45 +0100

hi *!

this template

<xsl:template match="d">
  ancestor axis: <xsl:for-each select="ancestor::*">
    <xsl:value-of select="name()"/>
  </xsl:for-each>

last element: <xsl:value-of select="name(ancestor::*[last()])"/>

</xsl:template>

will convert this source

<a>
  <b>
    <c>
      <d/>
    </c>
  </b>
</a>

into

ancestor axis: abc

last element: a

why?

the spec says that the ancestor axis is a reverse axis. but then the for-each statement would be wrong. from my understanding, it should produce "cba".

i found this explanation http://www.biglist.com/lists/xsl-list/archives/200405/msg00055.html in the archive, but i don't understand the concept of "steps". can anyone explain? sorry if this is a faq.

thanks,

jC6rn


--
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Current Thread
ancestor axis ordering (again...) Joern Nettingsmeier - 27 Feb 2006 13:44:09 -0000 <= Michael Kay - 27 Feb 2006 13:49:39 -0000

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