Re: Problem in grouping and filering.

You have a very common duplicate problem, the solution to which is in the
FAQ here:
http://www.dpawson.co.uk/xsl/sect2/N2696.html

In your case, you need something like this:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fo="http://www.w3.org/1999/XSL/Format" exclude-result-prefixes="fo">

  <xsl:output method="xml" indent="yes"/>

  <xsl:template match="hotels">
    <unique-longtext1s>
      <xsl:for-each select="rate-codes/ref[not(longtext1 =
following::longtext1)]">
        <xsl:copy-of select="longtext1"/>
      </xsl:for-each>
    </unique-longtext1s>
  </xsl:template>

</xsl:stylesheet>


Tested with Saxon.

Jay Bryant
Bryant Communication Services

----- Original Message ----- 
From: "Bamanie Kumarasena" <bkumarasena@xxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, January 16, 2006 12:43 AM
Subject:  Problem in grouping and filering.


> Hi,
>
>
> I am having the following XML ( similar one). I need to filter out the
minimum unique 3 rates. But I have no way of keeping a count in XSL
> , so I count by the preceding:: node. This counts with the duplicate
value. Is there a way to do this ?
>
> The XML I have :
> rates.xml
> ---------
>      <hotels>
> <rate-codes>
>     <rateperday>100</rateperday>
>             <ref>
>               <id>3</id>
>               <longtext1>Daily Leisue Rate</longtext1>
>               <longtext2></longtext2>
>             </ref>
>           </rate-codes>
>           <rate-codes>
> <rateperday>103</rateperday>
>             <ref>
>               <id>7</id>
>               <longtext1>Discounted Leisure Rate</longtext1>
>               <longtext2></longtext2>
>             </ref>
>           </rate-codes>
>           <rate-codes>
> <rateperday>107</rateperday>
>             <ref>
>               <id>8</id>
>               <longtext1>Discounted Leisure Rate</longtext1>
>               <longtext2></longtext2>
>             </ref>
>           </rate-codes>
>           <rate-codes>
> <rateperday>120</rateperday>
>             <ref>
>               <id>96</id>
>               <longtext1>Celebration Package - Lowry Hotel</longtext1>
>               <longtext2></longtext2>
>             </ref>
>           </rate-codes>
> ........
>       </hotels>
>
> I need to get all the unique rate details sorted according to rateperday
> and filtered the first 3 rates.
>
> rates.xsl
> -----------
> <xsl:template match="hotels">
>
> <xsl:variable name = "uniquelist"
> select =
> "rate-codes[not(ref/longtext1=following::rate-codes/ref/longtext1)]"/>
>  <xsl:for-each select="$uniquelist">
>     <xsl:sort select="rateperday" data-type="number"
> order="ascending"/>
>   <xsl:variable name="count"><xsl:value-of
> select="(count(preceding::rate-codes))"/></xsl:variable>
> <xsl:if test="$count &lt; 3">
> <xsl:value-of select="."/>
> </xsl:if>
> </xsl:for-each>
> </xsl:template>
>
> This is the xsl which I have, here I use the count:: preceding , but it
> counts the duplicates also. Please send me a quick response as this is
> quite urgent.
>
>
> The output I want is
>
> Daily Leisue Rate
> Discounted Leisure Rate
> Celebration Package - Lowry Hotel
>
> But the output I get is:
>
> Daily Leisue Rate
> Discounted Leisure Rate
>
>
> Thanks,
> Bamanie.
> -- 
> Bamanie Kumarasena
> Software Engineer ( JAVA)
> Open World Lanka (Pvt) Ltd, 41 Dutugamunu Street, Pamankada, Dehiwala,
> LK
> Tel: +94 11 4403904 Ext. 114
> Fax: +94 11 2854815
> http://www.openworld.org/
>
>
>
>
>
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