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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] xml not well-formed
 In the below example, I would like to make the div id = <xsl:value-of
select="Location"/>, but this will not work since it is not well-formed
xml. Is there any way to reference this node without using an xml element?
Thanks,
Dan
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<xsl:for-each select="songlist/song">
<div id="<xsl:value-of select="Location"/>"><xsl:value-of
select="Name"/></div>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
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